Wrapping up
TheoremEntropy form of PFR#
Suppose that \(G\) is a finite abelian group of torsion \(m\). Suppose that \(X\) is a \(G\)-valued random variable. Then there exists a subgroup \(H \leq G\) such that
Proof
Set \(X^0 := X\). By Existence of \(\tau\)-minimizer, there exists a \(\tau\)-minimizer \(X_{[m]} = (X_i)_{1 \leq i \leq m}\). By Vanishing entropy, we have \(D[X_{[m]}]=0\). By Minimizer close to reference variables and the pigeonhole principle, there exists \(1 \leq i \leq m\) such that \(d[X_i; X] \leq \frac{2}{\eta} d[X;X]\). By Vanishing, we have \(d[X_i;U_H]=0\) for some subgroup \(H \leq G\), hence by Ruzsa triangle inequality we have \(d[U_H; X] \leq \frac{2}{\eta} d[X;X]\). The claim then follows from \(\eta\).
Lean
Formalized as dist_of_X_U_H_le.
Sources
Uses 7 · Used by 1
Lemmapfr_aux_torsion#
Suppose that \(G\) is a finite abelian group of torsion \(m\). If \(A \subset G\) is non-empty and \(|A+A| \leq K|A|\), then \(A\) can be covered by at most \(K ^ {128m^3+1}|A|^{1/2}/|H|^{1/2}\) translates of a subspace \(H\) of \(G\) with
Proof
Repeat the proof of Lemma pfr_aux, but with Entropy form of PFR in place of Entropy version of PFR. Because of the lack of \(2\)-torsion, one has to use the Ruzsa triangle inequality to bound \(d[U,U]\) by \(2d[U,-U]\), costing an additional factor of \(2\) in the estimates.
Lean
Formalized as torsion_PFR_conjecture_aux.
Sources
Uses 8 · Used by 1
TheoremPFR#
Suppose that \(G\) is an abelian group of torsion \(m\) (not necessarily finite). If \(A \subset G\) is a finite non-empty set with \(|A+A| \leq K|A|\), then \(A\) can be covered by at most \(mK^{256m^3+1}\) translates of a finite subspace \(H\) of \(G\) with \(|H| \leq |A|\).
Proof
If \(G\) is finite, repeat the proof of PFR, but with Lemma pfr_aux_torsion in place of Lemma pfr_aux. In general, reduce to the finite span of \(A\) over \(\mathrm{Z}/m\mathrm{Z}\).
Lean
Formalized as torsion_PFR.
Sources
Uses 1
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