Sequence related to NOR… to $a(n) = \sum_{j=1}^{n} (3^j +…
TheoremSequence related to NOR bracketings#
\[a(n) = \sum_{j=0}^{n-1} (-1)^j \binom{2j}{j} \binom{2n-j-2}{n-j-1}\]References: - A112521
Quoted from FormalConjectures/OEIS/112521.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 6 test statements, counted here but not shown.
OeisA112521.conjecture
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a112521-formal-conjectures/blob/d4ee80e997c20209a1f18b7b9aa3521150d5474d/lean/OeisA112521Proof.lean#L876-L885.
Conjecture: Starting with \(n=1\), \(a(n)\) is the main diagonal of the array \(T(n, k)\).
theorem conjecture : ∀ (n : ℕ), n ≥ 1 → (a n : ℤ) = T n n
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/112521.lean, line 85.
Sources
TheoremA generalized Stern sequence#
A112970: A generalized Stern sequence, defined by the recurrence relations: \(a(2n+1) = a(n)\) and \(a(2n) = a(n) + a(n-2)\) with \(a(0)=1\), \(a(1)=1\) and \(a(n)=0\) for \(n \le -1\).
References: - A112970
Quoted from FormalConjectures/OEIS/112970.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 4 research or textbook statements: 4 solved. It also has 5 test statements, counted here but not shown.
OeisA112970.conjecture1
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a112970-formal-conjectures/blob/71ae72f443bd9bee7d958f0a19d9f9ec5ab82af5/lean/OeisA112970FC.lean#L43-L46.
Conjecture: \(a(2^n)=a(2^(n+1)+1)=\textrm{A033638}(n)\). This formalizes the equality \(a(2^n) = a(2^(n+1)+1)\).
theorem conjecture1 (n : ℕ) : a (2^n) = a (2^(n + 1) + 1)
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/112970.lean, line 77.
OeisA112970.conjecture1_value
Solved: stated here; a Lean proof is at https://github.com/anatoliiohorodnyk/lean-fc-proofs/blob/5da9642575b26c2c816a49bcb56b33fed5456619/Proofs/T_OeisA112970_conjecture1_value.lean#L139.
Second part of the conjecture, \(a(2^n)=\textrm{A033638}(n)=\lfloor n^2 / 4 \rfloor + 1\). It holds by induction on \(n\), since \(a(2^{n+1}) = a(2^n) + a(2^n - 2)\) for \(n \ge 1\) and \(a(2^m - 2) = \lfloor (m+1)/2 \rfloor\) for \(m \ge 1\).
theorem conjecture1_value (n : ℕ) : a (2^n) = n ^ 2 / 4 + 1
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/112970.lean, line 87.
OeisA112970.conjecture2
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a112970-formal-conjectures/blob/71ae72f443bd9bee7d958f0a19d9f9ec5ab82af5/lean/OeisA112970FC.lean#L56-L64.
Conjecture: \(a(2^n-1)=a(3*2^n-1)=1\). This formalizes the equality part \(a(2^n-1) = a(3*2^n-1)\).
theorem conjecture2 (n : ℕ) : a (2^n - 1) = a (3 * 2^n - 1)
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/112970.lean, line 98.
OeisA112970.conjecture3
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a112970-formal-conjectures/blob/71ae72f443bd9bee7d958f0a19d9f9ec5ab82af5/lean/OeisA112970FC.lean#L48-L54.
Conjecture: \(a(2^n-1)=a(3*2^n-1)=1\). This formalizes the value part \(a(2^n-1)=1\).
theorem conjecture3 (n : ℕ) : a (2^n - 1) = 1
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/112970.lean, line 106.
Sources
TheoremNumber of digits of n raised to the power of the sum of the digits of n#
References: - A113010
Quoted from FormalConjectures/OEIS/113010.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 5 test statements, counted here but not shown.
OeisA113010.conjecture
Open: stated without proof.
\(n=1\) and \(32\) are two fixed points. Are there any others?
theorem conjecture : ∃ n : ℕ, a n = n ∧ n ≠ 1 ∧ n ≠ 32
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113010.lean, line 59.
Sources
TheoremNumber of digits of n raised to the power of the digital root of n#
References: - A113019
Quoted from FormalConjectures/OEIS/113019.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 5 test statements, counted here but not shown.
OeisA113019.conjecture
Proved here.
\(n=1\) and \(32\) are fixed points. Are there any others?
Yes: 9^9 = 387420489 is also a fixed point. - Kenta Kitamura, Aug 14 2026
theorem conjecture : ¬ ∀ n : ℕ, a n = n → n = 1 ∨ n = 32
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113019.lean, line 69.
Sources
TheoremSmallest number \(m\) such that \(2^n - m\) and \(2^n + m\) are primes#
References: - A113213
Quoted from FormalConjectures/OEIS/113213.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 5 test statements, counted here but not shown.
OeisA113213.conjecture
Open: stated without proof.
Conjecture: \(a(n) = O(n^3)\).
The source defines \(a(n)\) as the least \(m\) with \(2^n - m\) and \(2^n + m\) prime, so it implicitly asserts that such an \(m\) exists. Since
a n = 0when no such \(m\) exists, the existence of a prime pair is stated explicitly for all sufficiently large \(n\).
theorem conjecture :
(∀ᶠ n : ℕ in Filter.atTop, ∃ m, (2 ^ n - m).Prime ∧ (2 ^ n + m).Prime) ∧
(fun n : ℕ => (a n : ℝ)) =O[Filter.atTop] (fun n : ℕ => (n ^ 3 : ℝ))
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113213.lean, line 66.
Sources
TheoremExpansion of g.f. \(-(1 - 48x^2 - 256x^3) / ((1 - 4x)(1 + 4x)(1 + 4x + 16x^2))\)#
Corresponds to m = 4 in a family of 4th-order linear recurrence sequences
This sequence is defined by the linear recurrence relation with signature \((-4, 0, 64, 256)\) and initial values \(a(0) = -1, a(1) = 4, a(2) = 32, a(3) = 64\). The recurrence is \(a(n) = -4 a(n-1) + 64 a(n-3) + 256 a(n-4)\).
References: - A113250
Quoted from FormalConjectures/OEIS/113250.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 5 test statements, counted here but not shown.
OeisA113250.conjecture
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a113249-family-square-terms-lean/blob/9b999db08344184285e8050c2722c845fd5f5309/lean/OeisA113249FamilyFC.lean#L106-L114.
Conjecture: \(a(m, 2n+1)\) is a perfect square for all \(m\) (see A113249). Specialized to \(m = 4\), which is A113250.
theorem conjecture : ∀ n : ℕ, IsSquare (a (2 * n + 1))
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113250.lean, line 69.
Sources
TheoremConjectures associated with A113252#
Corresponds to m = 6 in a family of 4th order linear recurrence sequences
This sequence is defined by the linear recurrence relation a(n) = -4 a(n-1) + 144 a(n-3) + 1296 a(n-4) for n > 3. Initial values are a(0) = -1, a(1) = 4, a(2) = 92, a(3) = 784.
References: - A113252
Quoted from FormalConjectures/OEIS/113252.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 5 test statements, counted here but not shown.
OeisA113252.conjecture
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a113249-family-square-terms-lean/blob/9b999db08344184285e8050c2722c845fd5f5309/lean/OeisA113249FamilyFC.lean#L116-L124.
Conjecture: \(a(m, 2n+1)\) is a perfect square for all \(m, n\) (see A113249). Specialized for \(m=6\), which is A113252.
theorem conjecture : ∀ n : ℕ, IsSquare (a (2 * n + 1))
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113252.lean, line 71.
Sources
TheoremSquare odd-indexed terms in the recurrence \(a(n) = 8a(n-1) - 8a(n-2) + 8a(n-3) - a(n-4)\)#
A113254: Corresponds to \(m = 8\) in a family of 4th-order linear recurrence sequences.
The sequence \(a(n)\) is defined by the initial conditions \(a(0)=-1, a(1)=4, a(2)=176, a(3)=3136\), and the linear recurrence relation \(a(n) = -4 * a (n-1) + 256 * a (n-3) + 4096 * a (n-4)\) for \(n \ge 4\).
References: - A113254 - arxiv/2605.22763 Advancing Mathematics Research with AI-Driven Formal Proof Search by George Tsoukalas et al.
Quoted from FormalConjectures/OEIS/113254.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 5 test statements, counted here but not shown.
OeisA113254.a_odd_is_square
Solved: stated here; a Lean proof is at https://github.com/mo271/formal-conjectures/blob/a32396489dcb8f86c3549b93aa358ac6a10a3a1f/FormalConjectures/OEIS/113254.wip.lean#L130.
Conjecture: \(a(8, 2n+1)\) is a perfect square for all \(n\) (see A113249).
A formal proof has been found with the methods described in arxiv/2605.22763.
theorem a_odd_is_square : ∀ n : ℕ, IsSquare (a (2 * n + 1))
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113254.lean, line 80.
Sources
TheoremConjectures associated with A113255#
Corresponds to m = 9 in a family of 4th-order linear recurrence sequences
This sequence is defined by the recurrence relation \(a(n) = -4 a(n-1) + 324 a(n-3) + 6561 a(n-4)\) for n > 3. Initial values are \(a(0) = -1, a(1) = 4, a(2) = 227, a(3) = 5329\).
References: - A113255
Quoted from FormalConjectures/OEIS/113255.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 5 test statements, counted here but not shown.
OeisA113255.conjecture
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a113249-family-square-terms-lean/blob/9b999db08344184285e8050c2722c845fd5f5309/lean/OeisA113249FamilyFC.lean#L126-L134.
Conjecture: \(a(m, 2n+1)\) is a perfect square for all \(m, n\) (see A113249). Specialized for \(m=9\), which is A113255.
theorem conjecture : ∀ n : ℕ, IsSquare (a (2 * n + 1))
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113255.lean, line 71.
Sources
TheoremAscending descending base exponent transform of squares#
a n is \(\sum_{i=1}^n (i^2)^((n-i+1)^2)\).
References: - A113257
Quoted from FormalConjectures/OEIS/113257.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 2 research or textbook statements: 2 open. It also has 5 test statements, counted here but not shown.
OeisA113257.conjecture1
Open: stated without proof.
The smallest prime in this sequence is \(a(2) = 5\). What is the next prime?
theorem conjecture1 :
conjecture1.answer = a (sInf {n : ℕ | 2 < n ∧ (a n).Prime})
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113257.lean, line 58.
OeisA113257.conjecture2
Open: stated without proof.
What is the first square value after 1?
theorem conjecture2 :
conjecture2.answer = a (sInf {n : ℕ | 1 < n ∧ IsSquare (a n)})
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113257.lean, line 68.
Sources
TheoremAscending descending base exponent transform of factorials#
References: - A113258
Quoted from FormalConjectures/OEIS/113258.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 4 test statements, counted here but not shown.
OeisA113258.conjecture
Open: stated without proof.
Is there a nontrivial power after \(a(4) = 5^3\)?
theorem conjecture :
∃ n > 4, ∃ b > 1, ∃ e > 1, a n = b ^ e
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113258.lean, line 57.
Sources
TheoremAscending descending base exponent transform of \(2^n\)#
References: - A113271
Quoted from FormalConjectures/OEIS/113271.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 8 test statements, counted here but not shown.
OeisA113271.conjecture1
Open: stated without proof.
The first prime terms in this (always odd) sequence are \(a(1) = 3\), \(a(3) = 41\), and \(a(4) = 593\). What is the next prime?
The OEIS comment currently says
$a(5) = 543$, but this conflicts with its defining formula, b-file, and examples: the actual index-five term is the composite number135457. Consequently the search for the next prime must begin after index4, not after index5.
theorem conjecture1 :
conjecture1.answer = a (sInf {n : ℕ | 4 < n ∧ (a n).Prime})
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113271.lean, line 80.
Sources
TheoremNumber of prime powers \(q<=n\) such that also \(q+2\) is a prime power#
References: - A113609
Quoted from FormalConjectures/OEIS/113609.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 5 test statements, counted here but not shown.
OeisA113609.conjecture
Open: stated without proof.
(25,27) is the smallest pair of prime powers (q,q+2) such that both q and q+2 are not primes, conjecture: there are more (but not < 10^6).
theorem conjecture :
∃ q ≥ 1000000,
IsOeisPrimePower q ∧ IsOeisPrimePower (q + 2) ∧
¬ q.Prime ∧ ¬ (q + 2).Prime
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/113609.lean, line 70.
Sources
TheoremDifference between first odd semiprime \(> 2^n\) and \(2^n\)#
References: - A114137
Quoted from FormalConjectures/OEIS/114137.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 2 research or textbook statements: 2 open. It also has 5 test statements and 1 API statement, counted here but not shown.
OeisA114137.conjecture1
Open: stated without proof.
In this powers of 2 sequence, does 1 occur infinitely often?
theorem conjecture1 :
Set.Infinite {n : ℕ | a n = 1}
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/114137.lean, line 106.
OeisA114137.conjecture2
Open: stated without proof.
Does every odd number occur?
theorem conjecture2 :
∀ k : ℕ, Odd k → ∃ n : ℕ, a n = k
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/114137.lean, line 114.
Sources
TheoremLargest odd divisor of \(a(n-1) + \textrm{prime}(n)\)#
\(a(0)=0\); thereafter \(a(n)\) = largest odd divisor of \(a(n-1) + \textrm{prime}(n)\).
References: - A114216
Quoted from FormalConjectures/OEIS/114216.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 6 test statements, counted here but not shown.
OeisA114216.conjecture
Open: stated without proof.
Is \(a(33900)\) the last term equal to \(1\)?
theorem conjecture :
∀ n > 33900, a n ≠ 1
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/114216.lean, line 85.
Sources
TheoremNumerator of \(\zeta(4n)/\zeta(2n)^2\) (with \(a(0)=2\) instead of \(-2\))#
The ratio \(\zeta(4n)/\zeta(2n)^2\) for \(n \ge 1\) is the rational number
\[ Q_n = -2 \frac{B_{4n}}{B_{2n}^2 \binom{4n}{2n}} \]where \(B_k\) is the \(k\)-th Bernoulli number. The sequence \(a(n)\) is the numerator of \(Q_n\), with \(a(0)\) defined as \(2\).
References: - A114362
Quoted from FormalConjectures/OEIS/114362.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 2 research or textbook statements: 1 open and 1 solved. It also has 4 test statements, counted here but not shown.
OeisA114362.conjecture1
Open: stated without proof.
Conjecture: if an integer \(n > 1\) is odd, then \(\zeta(2n)/\zeta(n)^2\) is irrational. Cf. W. Kohnen (link) and my conjecture in A348829. - Thomas Ordowski, Jan 05 2022
theorem conjecture1 (n : ℕ) (hn_gt_one : 1 < n) (hn_odd : Odd n) :
Irrational ((riemannZeta (2 * n : ℂ) / (riemannZeta (n : ℂ)) ^ 2).re)
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/114362.lean, line 89.
OeisA114362.conjecture2
Solved: stated here; a Lean proof is at https://github.com/chy4pro/formal-conjectures/blob/872759d0b464254d868f107fe7f9cf762900f57d/FormalConjectures/OEIS/114362.lean#L646.
Conjecture: \(\frac{1 - t(n)}{1 + t(n)} = \frac{1}{2^n} + \frac{1}{3^n} + \frac{1}{5^n} + \frac{1}{7^n} + O(\frac{1}{11^n})\), where \(t(n) = \zeta(2n)/\zeta(n)^2\). Cf. A348829. - Thomas Ordowski, Nov 13 2022
theorem conjecture2 :
(fun n : ℕ => (1 - t n) / (1 + t n) -
(1 / (2:ℝ)^n + 1 / (3:ℝ)^n + 1 / (5:ℝ)^n + 1 / (7:ℝ)^n))
=O[atTop] (fun n : ℕ => 1 / (11:ℝ)^n)
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/114362.lean, line 106.
Sources
TheoremEach term is previous term plus floor of harmonic mean of two previous terms.#
\(a(1) = 1, a(2) = 2\) and \(a(n) = a(n-1) + \lfloor \frac{2 a(n-1) a(n-2)}{a(n-1) + a(n-2)} \rfloor\) for \(n \ge 3\).
References: - A114831
Quoted from FormalConjectures/OEIS/114831.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 solved. It also has 4 test statements, counted here but not shown.
OeisA114831.conjecture3
Solved: stated here; a Lean proof is at https://github.com/KitaKen1/oeis-a114831-asymptotic/blob/54cdeeed2ef5838e3aa61a3a228e6867802d20df/lean/OeisA114831FC.lean#L252-L285.
Conjecture based on OEIS A114831: What is this sequence, asymptotically? If the limit exists, the ratio of consecutive terms must tend to \(\sqrt{3}\):
\[ \lim_{n \to \infty} \frac{a(n+1)}{a(n)} = \sqrt{3}. \]That's because \(a(n)\) is positive, monotonically increasing (\(a(n) > a(n-1)\)) and \(a(n+2) \geq a(n+1) + a(n)\). So \(a(n)\) grows exponentially, at least as fast as the Fibonnaci numbers. Assuming \(\frac{a(n+1)}{a(n)}\) tend to a limit L, solving for L in the definition of \(a(n)\) gives \(L=\sqrt{3}\).
theorem conjecture3 :
Tendsto (fun n ↦ (a (n + 1) : ℝ) / (a n : ℝ)) atTop (nhds (Real.sqrt 3))
Category research solved; AMS 11 Number theory. Declared in FormalConjectures/OEIS/114831.lean, line 80.
Sources
TheoremPartial sums of \(\binom{2n}{n}^2\)#
\[a(n) = \sum_{k=0}^n \binom{2k}{k}^2\]References: - A115257
Quoted from FormalConjectures/OEIS/115257.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 4 test statements, counted here but not shown.
OeisA115257.conjecture
Open: stated without proof.
Conjecture: For any positive integer n, the polynomials Sum_{k=0}^n binomial(2k,k)^2x^k and Sum_{k=0}^n binomial(2k,k)^2x^k/(k+1) are irreducible over the field of rational numbers. - Zhi-Wei Sun, Mar 23 2013
theorem conjecture :
∀ (n : ℕ), 1 ≤ n → Irreducible (polyP n) ∧ Irreducible (polyQ n)
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/115257.lean, line 70.
Sources
Theorem\(a(n)\) = the number of values of \(k <= 10^n\) such that \(\sqrt{k(k+1)(k+2)(k+3)+1}\) is prime#
Since \(\sqrt{k(k+1)(k+2)(k+3)+1} = k^2 + 3k + 1\), \(a(n) = \#\{k \in \mathbb{N} \mid 1 \le k \le 10^n \land (k^2 + 3k + 1) \text{ is prime} \}.\)
References: - A115366
Quoted from FormalConjectures/OEIS/115366.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 4 test statements, counted here but not shown.
OeisA115366.conjecture
Open: stated without proof.
Conjecture: \(a(n)/A006880(n) \rightarrow 1.77...\) where A006880(n) is the number of primes \(\le 10^n\).
theorem conjecture :
∃ L : ℝ,
Tendsto (fun n : ℕ => (a n : ℝ) / (Nat.primeCounting' (10 ^ n) : ℝ)) atTop (nhds L) ∧
1.77 ≤ L ∧ L ≤ 1.78
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/115366.lean, line 63.
Sources
Theorem\(a(n) = \sum_{j=1}^{n} (3^j + (-2)^j)\)#
References: - A116150
Quoted from FormalConjectures/OEIS/116150.lean in Formal Conjectures (Google DeepMind) at commit 2055e5ad, Apache-2.0, as are the docstrings and Lean statements below.
The file states 1 research or textbook statement: 1 open. It also has 5 test statements, counted here but not shown.
OeisA116150.conjecture
Open: stated without proof.
First primes are \(a(11) = 264353\) and \(a(17) = 193622861\). Additional primes: \(a(71)\), \(a(91)\), \(a(431)\). What is the next prime?
theorem conjecture : conjecture.answer = a (sInf {n : ℕ | 431 < n ∧ (a n).Prime})
Category research open; AMS 11 Number theory. Declared in FormalConjectures/OEIS/116150.lean, line 60.
Sources
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